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1337 <3 Problem

I guess that's what she gets for trying to do that online.

posted by The Living End
9/27/2009 7:24:51 PM

Views: 3008

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11 Comments

Current View: 15 / Show all Comments

rhuitron : LVL 39: VP 4.7: said:

Hidden (Show Comment) 15 votes

57 days 16 hours ago...

Needless to say, SkyWalkerGuy will always be a virgin.

....Unless he Fucks up somewhere, and goes to prison.

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The Chewbacca Defence : LVL 37: VP 4.5: said:

Hidden (Show Comment) 24 votes

57 days 15 hours ago...

Omfg, that is golden

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Smokey-69er : LVL 35: VP 4.3: said:

Hidden (Show Comment) 24 votes

57 days 7 hours ago...

the clue is in `skywalkerguy`

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SolarAbyss : LVL 42: VP 5: said:

Hidden (Show Comment) 4 votes

56 days 22 hours ago...

could also be the argument for a for loop

for (i=0;i<3;i++)

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Vinz : LVL 37: VP 4.5: said:

Hidden (Show Comment) 6 votes

53 days 4 hours ago...

The right way would be to say |i| < |3| which is mathematically correct.

\/ Edit: for z a complex number z = a + ib, we have |z| = sqrt(a^2 + b^2)
Now what?

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pyranos : LVL 41: VP 4.9: said:

Hidden (Show Comment) 3 votes

53 days 2 hours ago...

^ no, i is an imaginary number, taking its absolute value still doesn`t work. i^2 < 3 would work.

Edit "for z a complex number z = a + ib, we have |z| = sqrt(a^2 + b^2)
Now what?"

What, it doesn`t change the fact taking the absolute value of simply i which is imaginary can not be compared to the absolute value of 3. Not sure what you`re trying to prove using a complex number, other than showing what a complex number is. I could have missed the mark, calc was a long time for me. If thats the case i take my leave, spiked isn`t exactly the best place for this sort of discourse.

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